A Jar Contains 39 Red White And Blue Marbles

A jar contains 3 white 4 blue 5 red and 2 green marbles.

A jar contains 39 red white and blue marbles.

Find the probability of choosing the given marbles without replacement. Asked 03 25 15 suppose a jar contains 11 red marbles and 37 blue marbles. Now if you take out one red marble then there are 11 now in the jar. 1 2 chance we pick jar a 50 50 chance we pick a red marble 1 2 chance we pick jar b 0 50 chance we pick a red marble.

So to be absolutely certain you would have at least 3. If a marble is drawn at random from the jar what is the probability that the marble. You would try different combinations such as 25 of each colored marble in a jar or putting all red marbles in one jar and all the blue in the other. So the probability of drawing red is 3 12 or 1 4 reduced.

For the first marble the probably of getting a red would be 12 48 which is 1 4. A jar contains 2 red 1 white and 3 blue marbles. A are red b neither red or green c not white an ordinary pack of 77. Pulling out 2 marbles is the same as to taking out one marble and then taking out another marble form whats remaining in the jar.

Two marbles are drawn. We could potential remove 8 marbles and there is a possibility they could all be red. A jar contains a total of 20 marbles that are blue green or white. A jar contains 4 black marbles and 3 red marbles.

A draw the tree diagram for the experiment. We would need to remove 3 more marble to be absolutely certain there was at least three marbles of each color. If you reach in the jar and pull out 2 marbles at random find the probability that both are red. Next we could remove 7 more marbles and there is a possibility no matter how small they could all be blue.

The number of white marbles is three more than the number of green marbles and the number of blue marbles is one more than twice the number of green marbles b g w 20 w g 3 b 2g 1 substitute for b and w and solve for g 2g 1 g g 3 20 4g 4 20 4g. A jar contains 3 white marbles 4 red marbles and 5 blue marbles. See a solution process below. The probability of both happening would be 1 4 x 12 47.

You would still end up with a chance of 50. For the second marble the probability of getting a red would be 12 47. P red blue 2 p blue and blue answer by edwin mccravy 18224 show source. And there are still 5 white marbles.

Two marbles are drawn without replacement from a jar containing 4 black and 6 white marbles. You have 12 marbles total. Two marbles are drawn without replacement.